Answer:
Area of the given figure is 51.5 square units.
Step-by-step explanation:
Area of rectangle OCBH = Length × width
= 11 × 8
= 88 square units
Area of trapezoid OGEF = [tex]\frac{1}{2}(b_1+b_2)\times h[/tex]
= [tex]\frac{1}{2}(\text{GE+OF)}\times (\text{OG})[/tex]
= [tex]\frac{1}{2}(3+6)\times 4[/tex]
= 18 units²
Area of trapezoid GCDE = [tex]\frac{1}{2}(\text{GC+DE)}\times (\text{GE})[/tex]
= [tex]\frac{1}{2}(7+2)\times 3[/tex]
= 13.5 units²
Area of triangle AFH = [tex]\frac{1}{2}(\text{Base})\times (\text{Height})[/tex]
= [tex]\frac{1}{2}(5)(2)[/tex]
= 5 units²
Area of polygon ABCDEF = Area of rectangle CBHO - (Area of trapezoid OGEF + Area of trapezoid GCDE + Area of triangle AFH)
= 88 - (18 + 13.5 + 5)
= 88 - 36.5
= 51.5 units²
Therefore, area of the given polygon is 51.5 units²
