Answer:
The answer is
[H3O+] = 2.51 × 10^-13 M
Explanation:
To find the [H3O+] in the solution we must first find the pOH and the pH of the solution
That's
pH + pOH = 14
pH = 14 - pOH
To find the pOH we use the formula
pOH = - log [OH-]
[OH-] = 0.04 M
pOH = - log 0.04
pOH = 1.4
So the pH is
pH = 14 - 1.4
pH = 12.6
So the [H3O+] can be found by
pH = - log [H3O+]
12.6 = - log [H3O+]
Find the antilog of both sides
[H3O+] = 2.51 × 10^-13 M
Hope this helps you
