Answer:
The percentage of patients whose cholesterol is between 198 mg/dL and 207 mg/dL is 33.73%
Step-by-step explanation:
To calculate this proportion, we follow the probability route, using the z-score statistics
Mathematically;
z-score = (x-mean)/SD
from the question, mean = 200 and SD = 10
So for 198
z-score = (198-200)/10 = -2/10 = -0.2
For 207
z-score = (207-200)/10 = 7/10 = 0.7
So the probability we want to calculate is;
P(-0.2<z<0.7)
Mathematically this can be calculated as;
P(z<0.7) - P(z<-0.2)
We can calculate the required probability using the standard normal distribution table
P(-0.2<x<0.7) = 0.3373 from the standard distribution table
So it is this 0.3373 that we now convert to percentage and that is 33.73%
