Complete Question
A student bikes to school by traveling first dN = 0.900 miles north, then dW = 0.300 miles west, and finally dS = 0.100 miles south.
Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form.
Express your answer as two numbers separated by a comma. Be careful with your signs.
Answer:
The value is [tex]dT = ( -0.3, 0.8)[/tex]
Explanation:
From the question we are told that
The first displacement is [tex]dN = 0.900 \ due \ North[/tex] i.e positive y-axis
The second displacement is [tex]dW = 0.300 \ miles \ due \ west[/tex] i.e negative x-axis
The final displacement is [tex]dS = 0.100 \ miles \ due \ south[/tex] i.e negative y-axis
Generally dW in component for is
[tex]dW = (-0.3 , 0)[/tex]
Generally the total displacement of the student is mathematically represented as
[tex]dT = ( -0.3, (0.90 - 0.10))[/tex]
[tex]dT = ( -0.3, 0.8)[/tex]
