Answer:
h = 1.07 m
Explanation:
It is given that,
The average sped of the kingfisher, v = 4.6 m/s
Time, t = 1.4 s
Final speed, v = 0 (as it hits the water)
We need to find the height from which the bird dove. Let the height is h. According to the conservation of energy.
[tex]mgh=\dfrac{1}{2}mv^2\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{(4.6)^2}{2\times 9.8}\\\\h=1.07\ m[/tex]
So, the bird dove from a height of 1.07 m.
