The slope of a line in standard equation will be [tex]\frac{-A}{B}[/tex]
[tex]m=\frac{5}{4}[/tex]
The slope of a perpendicular line to this line will be opposite and reciprocal.
[tex]m=-\frac{4}{5}[/tex]
Then, we can plug in the point given to get the [tex]b[/tex] value.
[tex]3=-\frac{4}{5}(2)+b[/tex]
[tex]3=-\frac{8}{5}+b[/tex]
[tex]b=\frac{23}{5}[/tex]
[tex]y=-\frac{4}{5}x+\frac{23}{5}[/tex]
Hope this helps.
頑張って!
