Answer:
[tex]x^3+2x^2-5x-6[/tex]
note this isn't the only possible answer; read below.
Step-by-step explanation:
For quadratic formulas when you foil the equation you can easily identify the root values by setting them equal to 0 and solving for X. Note that a quadratic is of 2 degree so you get 2 root values. Now, instead of 2, you have 3.
So... they give you the zeros x=2 and x=-1, now add your own random x value.
(x-2)(x+1)(x+3)
Now you can foil it into a polynomial equation.
