Answer:
Net force = 7.10 N
Direction of the resultant force = 45° from the horizontal in South-west direction
Explanation:
Forces acting on opposite directions horizontally are 10N and 5N.
Resultant force horizontally F(1) = 10 - 5 = 5N (in the direction of 10 N)
Forces acting on opposite directions vertically are 7N and 2N.
Resultant force vertically F(2) = 7 - 2 = 5N (in the direction of 7N)
Now resultant force of F(1) and F(2),
F = [tex]\sqrt{(F_1)^2+(F_2)^2}[/tex]
F = [tex]\sqrt{5^2+5^2}[/tex]
F = [tex]5\sqrt{2}[/tex] ≈ 7.10 N
From the triangle OBC,
tanθ = [tex]\frac{\text{BC}}{\text{OB}}[/tex]
tanθ = [tex]\frac{1}{1}[/tex]
θ = 45°
Therefore, magnitude of the resultant force = 7.10N
Direction of the resultant force = 45° from the horizontal in south west direction.
