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What if boy A and boy B pull the heavy cabinet at the same time in opposite directions with 10N and 5N of force perspectively, what will be the net force on the cabinet?

Respuesta :

Answer:

Explanation:

Boy b will win and cabinate will move in his direction

15 is maybe the net force

A force is a vector quantity, and the net force on an object is the vector sum of all the forces acting on the object

The net force on the cabinet is 5 Newtons in the direction boy A is pulling

The reason the net force value is correct is given as follows

The known parameter are;

  • Force with which boy A pulls the cabinet = 10 N
  • Force with which boy B pulls the cabinet = 5 N
  • The direction boy B pulls the cabinet = Opposite direction to the direction boy A pulls the cabinet

Required:

The net force on the cabinet

Solution:

Let the vector form of the force applied by boy A, [tex]\overset \rightarrow {F_1}[/tex] = 10·i, therefore, the force applied by boy B in the opposite direction is, [tex]\overset \rightarrow {F_2}[/tex] = -5·i

The net force on the cabinet,  [tex]F_{NET}[/tex] = [tex]\overset \rightarrow {F_1}[/tex] + [tex]\overset \rightarrow {F_2}[/tex], therefore;

[tex]F_{NET}[/tex] = 10·i - 5·i = 5·i

  • The net force on the cabinet, [tex]F_{NET}[/tex] = 5 Newton, in the direction of boy A

Learn more about net force here:

https://brainly.com/question/14361879

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