7. In the lectures an example was given of how the Fermi levels were filled. There were 20 electrons with a total energy of 106 eV. The states were 1 eV apart, starting at 1/2 eV. Pauli exclusion limits the number of electrons per level to 2. a. Find the 24 allowed distributions. b. What is the average occupancy of each energy state

Respuesta :

Answer:

F(e) = [tex]\frac{1}{1 + e^{(e-ef)/kt} }[/tex]

Explanation:

A) Determine the 24 allowed distributions

attached below

B ) The average occupancy of each energy state

F(e) = [tex]\frac{1}{1 + e^{(e-ef)/kt} }[/tex]

for the best fit/condition to determine the average occupancy of each energy state

Ef ( fermi energy ) = 9.998 eV

Kt = 1.447 eV

T = 16800 k

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