Answer:
length: 200
width: 65
Step-by-step explanation:
length: 3w + 5
width: w
perimeter = 2L + 2W
530 = 2(3w + 5) + 2w
530 = 6w + 10 + 2w
530 = 8w + 10
520 = 8w
w = 65
length: 3w + 5 = 3(65) + 5 = 200
width: w = 65
Width and length of rectangle is 65 feet and 200 feet
Given:
Perimeter of rectangular skating rink = 530 feet
Length is 5 feet more than 3 times width
Find:
Dimensions of rectangle
Computation:
Assume;
Width of rectangle = a feet
So,
Length of rectangle = (3a + 5) feet
Perimeter of rectangle = 2(l + b)
2[(3a + 5) + a] = 530
2[4a + 5] = 530
8a + 10 = 530
8a = 520
a = 65
Width of rectangle = a feet
Width of rectangle = 65 feet
Length of rectangle = (3a + 5) feet
Length of rectangle = 3(65) + 5 feet
Length of rectangle = 200 feet
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