Un avión de rescate en Alaska deja caer un paquete de provisiones a un grupo de exploradores extraviados. Si el avión viaja horizontalmente a 40 m/s y una altura de 100 m sobre el suelo, ¿Donde cae el paquete en relación con el punto que se soltó?

The package in relation to the point where it was released falls a certain distance that is calculated by applying the horizontal motion formulas , as the horizontal speed of the plane and the height above the ground are known, the time that It takes the package to reach its destination and then the horizontal distance (x) is calculated from where it was dropped, as follows:

[tex]$V_{ox}=v_x = 40 \ m/s$[/tex]

h = 100 m

x =?

Height formula h:

[tex]$h=g \times \frac{t^2}{2}$[/tex]

Time t is cleared:

[tex]$t = \sqrt{\frac{2h}{g}}$[/tex]

[tex]$t = \sqrt{\frac{2 \times 100}{9.8}}$[/tex]

t = 4.51 sec

Horizontal distance formula x:

[tex]$x=V_x \times t$[/tex]

x = 40 m / sec x 4.51 sec

x = 180.4 m