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What is the gravitational force between two identical 50,000 kg asteroids whose centers of mass are separated by 1000 m?

Respuesta :

Answer:

The gravitational force between the two masses is 1.668575 × 10⁻¹¹ N

Explanation:

The given parameters are;

The mass of the two asteroids having gravitational attraction, are m₁ = m₂ = m = 50,000 kg

The separation distance between their centers, r = 1,000 m

The gravitational attraction force, F, between the two masses is given as follows;

[tex]F =G\dfrac{m_{1}m_{2}}{r^{2}}[/tex]

Where;

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m₁ = m₂ = m

Substituting the values gives;

[tex]F =6.67430 \times 10^{-11} \times \dfrac{50,000 \times 50,000}{1000^{2}} = 1.668575 \times 10^{-7} \ N[/tex]

The gravitational force, F, between the two masses = 1.668575 × 10⁻¹¹ N.

The gravitational force between the two identical asteroids is 1.67 × 10⁻⁷ Newton.

Given the data in the question

Since the asteroids are identical

  • Mass of the asteroids; [tex]m_1 = m_2 = 50000kg[/tex]
  • Distance between the centers of the masses; [tex]r = 1000m[/tex]

Gravitational force; [tex]F =\ ?[/tex]

To determine the gravitational force between two identical asteroids, we use the Newton's law of universal gravitation:

[tex]F = G\frac{m_1m_2}{r^2}[/tex]

Where [tex]m_1[/tex] is mass of object 1, [tex]m_2[/tex] is mass of object 2, r is the distance between centers of the masses and G is the Gravitational constant ( [tex]6.67408 * 10^{-11} m^3/kgs^2[/tex] )

We substitute our values into the equation

[tex]F = (6.67408 * 10^{-11} m^3/kgs^2) \frac{50000kg*50000kg}{(1000m)^2} \\\\F = \frac{0.166852kgm^3/s^2}{1000000m^2}\\\\ F = 1.67 * 10^{-7}kg.m/s^2\\\\F = 1.67 * 10^{-7}N[/tex]

Therefore, the gravitational force between the two identical asteroids is 1.67 × 10⁻⁷ Newton.

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