Solve the following equation algebraically: -16 = 16x^2 How many solutions does this equation have? Explain. a. -1=x^2: One solution because only -1 will satisfy the equation. b. -1=x^2: No real solution because there is no real number that, when squared, produces -1. C. 1=x^2: Two solutions because the square root of 1 is positive 1 and negative 1. d. 1=-x^2: One solution because only -1 will satisfy the equation.
