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How much heat is necessary to vaporize 685 g of H20 at 100°C? The heat of vaporization
of H2O is 540 cal/g.
0 370,000 cal
O 1.22 x 103 cal
O 88,400 cal
01.27 kcal
h
Question 8
3.33 pts

Respuesta :

dsdrajlin

Answer:

370,000 cal

Explanation:

Step 1: Given data

  • Mass of water (m): 685 g
  • Heat of vaporization of water (ΔH°vap): 540 cal/g

Step 2: Calculate the heat necessary to vaporize 685 g of water

Vaporization is the process in which a liquid converts to a gas, at a constant temperature. The heat required (Q) is:

Q = ΔH°vap × m

Q = 540 cal/g × 685 g

Q = 3.70 × 10⁵ cal

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