Answer:
it takes him 22.36 seconds to cover that distance
Explanation:
We can solve this problem using the kinematic equation for uniformly accelerated motion:
[tex]x_f-x_i=v_0*t\,+\,\frac{1}{2} a\,*\,t^2[/tex]
which replacing the values given for our case becomes:
[tex]375=0*t\,+\,\frac{1}{2} (1.5)\,t^2\\375=\frac{1}{2} (1.5)\,t^2[/tex]
and which solving for t gives:
[tex]375=\frac{1}{2} (1.5)\,t^2\\t^2=2*375/1.5\\t^2=500\\t=\sqrt{500} \\t \approx 22.36\,\,sec[/tex]
