In a hydraulic lift, a 620 N force is exerted on a 0.20 m2 piston in order
to support a weight that is placed on a2.0 m2 piston. How much pressure is
exerted on the narrow piston? How much weight(force) can the wide piston lift?

Respuesta :

Answer:

Pressure on the narrow piston = 3100 [tex]N/m^2[/tex]

The wider piston can lift the weight up-to 6200 N

Explanation:

Given that the area of the narrow piston = 0.2 [tex]m^2[/tex]

Applied force on the narrow piston, [tex]F_{in}[/tex]= 620 N

Area of the larger piston  = 2.0 [tex]m^2[/tex].

As pressure = force/ area,

So. pressure exerted on the narrow piston, [tex]P= 620/0.2=3100 N/m^2[/tex]

There is liquid in between the narrow piston and the larger piston and according to Pascal's law, the pressure inside any liquid is uniformly distributed.

As the narrow piston is applying the pressure on the liquid which is equal to the external pressure applied on the narrow piston, i.e 3100 [tex]N/m^2[/tex].

So, the uniformly distributed pressure in the fluid is 3100 [tex]N/m^2[/tex].

Now, the liquids apply pressure on the larger piston,

as force = Area x pressure, so the applied on the larger piston, [tex]F_{out}[/tex], by the liquid is

[tex]F_{out} = 3100\times2=6200[/tex] N

Hence, the wider piston can lift the weight up-to 6200 N.