Answer:
note: all the twos are to the power
100=(x−1)2(y+3)
Step-by-step explanation:
Suppose the centre of the circle was at the origin (where the x axis crosses the y axis). Then the equation would be:
r2=x2+y2
The reason for this format is that the length of the radius (which is of fixed length) can be related to x and y by Pythagoras. However, the circle centre is not at the origin. It is at
(x,y)→(1,−3)
So we can mathematically make this work by 'theoretically' moving the actual centre to a new centre located at the origin.
Thus we would have:
r2=(x−1)2+(y−(−3))2
r2=(x−1)2+(y+3)2
But the radius is 10 so we have
(10)2=(x−1)2+(y+3)2
100=(x−1)2+(y+3
