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b) In the given figure, show that triangle PQR is a right angled triangle.

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mlarsen5000 mlarsen5000 · Answer 1 · 2021-01-02T15:09:08+01:00

Answer:

Given that triangle RSP is a right triangle, then using the Pythagorean Theorem, RP = 5. (3²+4²=5²)

Plugging the 5 in to triangle RPQ, we find that the Theorem still works for that one, which means it is a right triangle (5²+12²=13²)

Step-by-step explanation:

Given that triangle RSP is a right triangle, then using the Pythagorean Theorem, RP = 5. (3²+4²=5²)

Plugging the 5 in to triangle RPQ, we find that the Theorem still works for that one, which means it is a right triangle (5²+12²=13²)

jimrgrant1 jimrgrant1 · Answer 2 · 2021-01-02T15:13:10+01:00

Answer:

see explanation

Step-by-step explanation:

Using Pythagoras' identity in Δ PRS

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, then

PR² = 3² + 4² = 9 + 16 = 25 ( take the square root of both sides )

PR = [tex]\sqrt{25}[/tex] = 5

Using the converse of Pythagoras in Δ PQR

If the longest side squared is equal to the sum of the squares on the other 2 sides then the triangle is right.

QR² = 13² = 169

PR² + PQ² = 5² + 12² = 25 + 144 = 169

Thus Δ PQR is a right triangle, with right angle at P