Answer:
t= (20, 25, ... 40) s
Explanation:
This is an exercise in kinematics specifically of uniform motion, the first thing we must do is set a reference system, we place our zero in the police car, we write the equations
police car
x₁ = v₁ t
truck
x₂ = x₀ + v₂ t
In this case, they indicate several initial positions of the truck and the speed of the two vehicles, at the meeting point the positions must be the same
x₁ = x₂
v₁ t = x₀ + v₂ t
t (v₁ - v₂) = x₀
t = [tex]\frac{x_{o} }{v_{1}- v_{2} }[/tex]
let's calculate for each initial position
x₀ = 80m
t = 80 / (25-21)
t = 80/4
t = 20 s
x₀ = 100 m
t = 100/4
t = 25 s
the last x₀ = 160 m
t = 160/4
t = 40 s
we can see that the time increases as the distance between the vehicles increases
