Answer:
c = 5505263.16 J/g.°C
Explanation:
Given data:
Mass of ring = 12 mg (12/1000 = 0.012 g)
Calories used = 30.0 cal (30.0 ×4184 = 125520 J)
Temperature increases = 1.9°C
Specific heat of ring = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
125520 J = 0.012 g×c ×1.9°C
125520 J = 0.0228 g.°C ×c
c = 125520 J / 0.0228 g.°C
c = 5505263.16 J/g.°C
