Actual yield : 45.752 g ⇒no option
Given
The theoretical yields of Cl₂ : 65.35 g and 68.08 g
Required
The actual yield
Solution
Reaction
4 HCl (aq) + MnO₂ (s) → MnCl₂ (aq) + Cl₂ (g) + 2H₂O (l)
Because there are two theoretical yields, then we can choose the smallest one because the value is usually determined from the limiting reactant (in this reaction the limiting reactant is MnO₂)
So 65.36 g is The theoretical yields of Cl₂
Then the actual yield :
[tex]\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\actual=\%yield\times theoretical\\\\actual=70\%\times 65.36=45.752[/tex]
