Answer:
A) 2x²y³[tex]\sqrt{7xy^2}[/tex]
Step-by-step explanation:
[tex]\sqrt[3]{56x^7y^5}[/tex] = [tex]\sqrt[3]{(2^3)(7)(x^3)(x^3)(x)(y^3)(y^2)}[/tex] anything inside the radical raised to
the third power can be removed to
the outside of the radical
= 2(x)(x)(y) · [tex]\sqrt[3]{(7)(x)(y^2)}[/tex]
= 2x²y·[tex]\sqrt[3]{(7)(x)(y^2)}[/tex]
