Answer:
[tex]3n+6\geq 12[/tex]
Step-by-step explanation:
Given :The sum of three times a number and 6 is at least 12.
To Find:Write an inequality for the given statement
Solution:
Let n be the number
So, 3 times of a number = 3n
Now Sum of three times of a number and 6 = 3n+6
Since we are given that the sum of three times a number and 6 is at least 12(i.e. equal to or greater than 12)
So, A.T.Q.
[tex]3n+6\geq 12[/tex]
Thus an inequality for the given statement: the sum of three times a number and 6 is at least 12 is [tex]3n+6\geq 12[/tex]
