Respuesta :
Answer:
The probability of having green and wrinkled seeds is equal to [tex]6.25[/tex]%
Explanation:
Here R allele is dominant over r allele and Y allele is dominant over y allele.
Thus, a green phenotype will have genotype rr
and a wrinkled phenotype will have genotype yy
The punnet square representing the cross between RrYy and RrYy is as follows -
RY Ry rY ry
RY RRYY RRYy RrYY RrYy
Ry RRYy RRyy RrYy Rryy
rY RrYY RrYy rrYY rrYy
ry RrYy Rryy rrYy rryy
Out of all 16 offspring, only one offspring with genotype "rryy" represents green and wrinkled seeds.
Thus, the probability of having green and wrinkled seeds is equal to
[tex]\frac{1}{16} * 100\\= 6.25[/tex]%
Answer:
Probability of green and wrinkled seeds is [tex]\frac{1}{16}[/tex]
Explanation:
Here ,
"R" represents the allele for round seeds
and "r" represents the allele for wrinkled seeds
"Y" represents the allele for yellow seeds and
"y " represents the allele for green seeds
Thus,
Dihybrid cross for round and yellow seeds (RrYy) means that the round allele is dominant overwrinkled seeds and yellow is dominant over green color seed
RrYy * RrYy
RY Ry rY ry
RY RRYY RRYy RrYY RrYy
Ry RRYy RRyy RrYy Rryy
rY RrYY RrYy rrYY rrYy
ry RrYy Rryy rrYy rryy
Round & Yellow seeds- RRYY, RRYy, RrYY, RrYY, RRYy, RrYy, RrYY, RrYy, RrYy
Round & Green seeds – RRyy, Rryy, Rryy
Wrinkled & Yellow Seeds – rrYY, rrYy, rrYY
Wrinkled &green seeds - rryy
Number of green and wrinkled seeds - 1
Probability of green and wrinkled seeds is [tex]\frac{1}{16}[/tex]
