Answer:
Mass = 25.08 g
Explanation:
Given data:
Volume of fluorine = 29.6 L
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Mass of fluorine = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1 atm × 29.6 L / 0.0821 atm.L/ mol.K × 273.15 K
n = 1.32 mol
Mass of fluorine:
Mass = number of moles × molar mass
Mass = 1.32 mol ×19 g/mol
Mass = 25.08 g
