Answer:
222.2N/m
Explanation:
Given parameters:
Elastic potential energy = 4000J
Extension = 6m
Unknown:
Spring coefficient = ?
Solution:
The elastic potential energy is the energy stored within a string.
It is expressed as;
EPE = [tex]\frac{1}{2}[/tex] k e²
k is the spring constant
e is the extension
4000 = [tex]\frac{1}{2}[/tex] x k x 6²
8000 = 36k
k = 222.2N/m
