Given that y =c(x)=^3√x . solving for the value of y for x = 0, 0.008, 0.027, 0.064, 0.125, 0.216, 0.343, 0.512, 0.729, and 1. The value of y with its corresponding x are:
X y
0 0
0.008 0.2
0.027 0.3
0.064 0.4
0.125 0.5
0.216 0.6
0.343 0.7
0.512 0.8
0.729 0.9
1 1
Step-by-step explanation:
We are given a function as:
[tex]y=c(x)=\sqrt[3]{x}[/tex]
We have to find the value of the function at different values of x:
1)
when x=0
[tex]y=\sqrt[3]{0}\\\\y=0[/tex]
Hence, y=0
2)
when x=0.008
[tex]y=\sqrt[3]{0.008}\\\\y=\sqrt[3]{(0.2)^3}\\\\y=0.2[/tex]
Hence y=0.2
3)
when x=0.027
[tex]y=\sqrt[3]{0.027}\\\\y=\sqrt[3]{(0.3)^3}\\\\y=0.3[/tex]
Hence, y=0.3
4)
when x=0.064
[tex]y=\sqrt[3]{0.064}\\\\y=\sqrt[3]{(0.4)^3}\\\\y=0.4[/tex]
Hence, y=0.4
5)
when x=0.125
[tex]y=\sqrt[3]{0.125}\\\\y=\sqrt[3]{(0.5)^3}\\\\y=0.5[/tex]
Hence, y=0.5
6)
when x=0.216
[tex]y=\sqrt[3]{0.216}\\\\y=\sqrt[3]{(0.6)^3}\\\\y=0.6[/tex]
Hence, y=0.6
7)
when x=0.343
[tex]y=\sqrt[3]{0.343}\\\\y=\sqrt[3]{(0.7)^3}\\\\y=0.7[/tex]
Hence, y=0.7
8)
when x=0.512
[tex]y=\sqrt[3]{0.512}\\\\y=\sqrt[3]{(0.8)^3}\\\\y=0.8[/tex]
Hence, y=0.8
9)
when x=0.729
[tex]y=\sqrt[3]{0.729}\\\\y=\sqrt[3]{(0.9)^3}\\\\y=0.9[/tex]
Hence, y=0.9
10)
when x=1
[tex]y=\sqrt[3]{1}\\\\y=\sqrt[3]{(1)^3}\\\\y=1[/tex]
Hence, y=1
