Answer:
4 cm
Step-by-step explanation:
In order to solve this problem we just have to remember the formula for the area of the rectangle:
[tex]A=L*W[/tex]
Now we have to represent the values for width and lenth, we are going to use X for the width, and if the length is twice as much the width and is one foot more it will be represented by: 2x+1
So if we put the values into the formula we get an equation:
[tex]A=(x)(x+1)\\A=x^{2} +x\\36=x^{2} +x\\x^{2} +x-36=0[/tex]
Now that we have our equation we can solve by factorizing it:
[tex]x^{2}+x-36=0\\ (x+9)(x-4)=0[/tex]
Once we have the two factors we just equalize them to 0
And solve it for (x-4):
[tex]x-4=0\\x=4[/tex]
So the width of the rectangle is 4 and the length is 9.
