Respuesta :

sebassandin

Answer:

About two times faster.

Explanation:

Hello!

In this case, since we need a k2/k1 ratio to figure out the increase in the reaction rate for a chemical process, we need to use the following version of the Arrhenius equation:

[tex]ln(\frac{k_2}{k_1} )=-\frac{Ea}{R}(\frac{1}{T_2} -\frac{1}{T_1} )[/tex]

Thus, we plug in Ea, R and the temperatures to obtain:

[tex]ln(\frac{k_2}{k_1} )=-\frac{50,000J/mol}{8.314J/mol*K}(\frac{1}{322K} -\frac{1}{310.0K} ) \\\\ln(\frac{k_2}{k_1} )=0.723[/tex]

Now, we use exponential to obtain:

[tex]\frac{k_2}{k_1} =exp(0.723)\\\\\frac{k_2}{k_1}=2.1[/tex]

Thus, we infer that the reaction is about two times faster.

Best regards!

okpalawalter8

We have that at temperature of 325k reaction will be 2.45 times faster than at 310k.

Speed of reaction

Question Parameters:

Generally the Arrhenius  equation  is mathematically given as

[tex]log\frac{k^2}{k^1}=\frac{Ea}{2.303R}(\frac{1/t1}{1/t2})\\\\Therefore\\\\log\frac{k^2}{k^1}=\frac{50e3}{2.3038.314}(\frac{1/310}{1/325})1/k\\\\log\frac{k^2}{k^1}=\frac{2611.35*15}{310*325}\\\\K2=2.45*k1\\\\[/tex]

Therefore, we infer that

At Temperature of 325k reaction will be 2.45 times faster than at 310k.

For more information on Temperature visit

https://brainly.com/question/13439286

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