janessa0804
contestada

Graph the function f(x)=x^2+4x- 12 on the coordinate plane. (do a, b and c)(explain or show how you know the answer.) (graph down below.)

a) What are the x-intercepts?
(b) What is the y-intercept?
(c) What is the maximum or minimum value?

Graph the function fxx24x 12 on the coordinate plane do a b and cexplain or show how you know the answer graph down below a What are the xintercepts b What is t class=

Respuesta :

sqdancefan

9514 1404 393

Answer:

  a) {-6, 2}

  b) -12

  c) minimum: -16

Step-by-step explanation:

I find a graphing calculator to be a big help. Its graph is attached.

__

a) The function can be factored as ...

  f(x) = (x -2)(x +6)

The factors are zero at the x-intercepts: x = 2, x = -6.

__

b) The y-intercept is the function value when x=0. That is the constant in the function. The y-intercept is -12.

__

c) The leading coefficient of the function is positive, so its graph opens upward. The extreme value is a minimum. It is found on the axis of symmetry, at the x-value that is halfway between the x-intercepts: x = (2-6)/2 = -2. The function value there is ...

  f(-2) = (-2-2)(-2+6) = -4(4) = -16

The minimum is f(-2) = -16.

Ver imagen sqdancefan

Otras preguntas