Answer:
Total amount of alum lost = 0.5122 grams
Explanation:
Let the total volume of the solution be 100 mL
In 100 mL of solution, there is 2.63 gram of alum.
Out of this 100 mL solution, 42.5 mL is remaining.
Amount of alum in 42.5 mL solution is
[tex]\frac{42.5}{100} * 2.63 = 1.117\\[/tex] grams
Now the amount of alum lost is [tex]2.63 -1.117 = 0.5122[/tex] grams
