Answer:
0.131mol
Explanation:
Firstly, we need to find the number of moles of chlorine gas (Cl2) by using the formula:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas constant (0.0821 Latm/molK)
T = temperature (K)
Using PV = nRT
n of Chlorine = PV/RT
Based on the information provided in this question, V = 2.12 L, P = 2.27atm, T = 24°C = 24 + 273 = 297K
n = 2.27 × 2.12/ 0.0821 × 297
n = 4.8124/24.3837
n = 0.197
number of moles of Chlorine gas = 0.197mol
The balanced chemical equation provided in this question is as follows;
2 Al(s) + 3Cl2 (g) → 2AlCl3 (s)
3 moles of Cl2 produce 2 moles of AlCl3
0.197moles of Cl2 will produce;
0.197 × 2/3
= 0.394/3
= 0.131mol of AlCl3.
