Answer:
0.063 Kg
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 10 Hz
Spring constant (K) = 250 N/m
Mass (m) =?
Next, we shall determine the period of oscillation. This can be obtained as follow:
Frequency (f) = 10 Hz
Period (T) =?
T = 1/f
T = 1/10
T = 0.1 s
Finally, we shall determine the mass of the spring. This can be obtained as follow:
Spring constant (K) = 250 N/m
Period (T) = 0.1 s
Pi (π) = 3.14
Mass (m) =?
T = 2π√(m/K)
0.1 = 2 × 3.14 × √(m/250)
0.1 = 6.28 × √(m/250)
Divide both side by 6.28
0.1 / 6.28 = √(m/250)
Take the square of both side.
(0.1 / 6.28)² = m/250
Cross multiply
m = (0.1 / 6.28)² × 250
m = 0.063 Kg
Therefore, the mass of the spring is 0.063 Kg.
