Answer:
2.9 cm³
Step-by-step explanation:
Note: For the copper and the lead to balance, they must have thesame mass.
Applying,
D' = m'/V.................... Equation 1
Where D' = density of the lead, m' = mass of the lead, V = Volume of the lead.
make m' the subject of the equation
m' = D'V................ Equation 2
From the question,
Given: D' = 11.4 g/cm³, V = 2.28 cm³
Substitute these values into equation 2
m' = (11.4×2.28)
m' = 25.992 g
Similarly,
for copper,
D = m/V............... Equation 3
Where D = density of copper, m = mass of copper, V = volume of copper.
make V the subject of the equation
V = m/D.............. Equation 4
where, m = m' = 25.992 g
Given: D = 8.96 g/cm³
Substitute these values into equation 4
V = 25.992/8.96
V = 2.9 cm³
