Answer:
..........
Step-by-step explanation:
Given:
The height of the ladder = 15 m
When the ladder leans at point B from the ground level, then it makes an angle of 52° with the horizontal
When the ladder leans at point A from the ground level, then it makes an angle of 85° with the horizontal
To find:
The distance between point A and point B is?
Solution:
To solve the above-given problem, we will use the following trigonometric ratio of a triangle:
Referring to the figure attached below, we will assume,
BD = AD = 15 m = height of the ladder
∠BDC = 52° = angle of elevation to the foot of the window
∠ADC = 85° = angle of elevation to the top of the window
Now,
In ΔBCD, we have
Opposite side = BC
Hypotenuse = BD = 15 m
θ = 52°
∴
and
In ΔACD, we have
Opposite side = AC
Hypotenuse = AD = 15 m
θ = 85°
∴
∴ The height of the window, AB = AC - BC = 14.94 m - 11.82 m = 3.12 m
Thus, the distance between point A and point B is 3.12 m.
-----------------------------------------------------------------------------------------------
Also View:
A ladder leaning against a wall makes an angle of 60 degree with the horizontal If the foot of the ladder is 2.5 m away from the wall , find the length of the ladder.
