Answer:
Exercise Problem Solution
1 Find the perimeter of a triangle the sides of which are 10 in, 14 in and 15 in. P = 10 in + 14 in + 15 in = 39 in
2 A rectangle has a length of 12 cm and a width of 4 cm. Find its perimeter. P = 12 cm + 12 cm + 4 cm + 4 cm = 32 cm
3 Find the perimeter of a regular hexagon with each side measuring 8 m. P = 6(8 m) = 48 m
4 The perimeter of a square is 20 ft. How long is one side? 20 ft ÷ 4 = 5 ft
5 The perimeter of a regular pentagon is 100 cm. How long is one side? 100 cm ÷ 5 = 20 cm
Step-by-step explanation:
Answer:
61 square feet
Step-by-step explanation:
Your rectangle has a area of A = w l
A = 4*10 = 40
The triangle has a area of A = h (b/2)
A = 7 (6/2)
A = 21
Add both for the area
