Answer:
Step-by-step explanation:
From the picture attached,
m∠COB = 90° - m∠BOS
= 90° - 40°
= 50°
tan(30°) = [tex]\frac{AC}{OC}[/tex]
[tex]\frac{1}{\sqrt{3}}=\frac{AC}{OC}[/tex]
AC = [tex]\frac{OC}{\sqrt{3}}[/tex] ------(1)
Similarly, tan(50°) = [tex]\frac{BC}{OC}[/tex]
BC = OC[tan(50°)] -------(2)
Now AC + BC = 30 cm
By substituting the values of AC and BC from equation (1) and (2),
[tex]\frac{OC}{\sqrt{3}}+OC(\text{tan}50)=30[/tex]
(1.769)OC = 30
OC = 16.96
1). cos(30°) = [tex]\frac{OC}{AO}[/tex]
[tex]\frac{\sqrt{3}}{2}= \frac{16.96}{OA}[/tex]
[tex]OA=19.58[/tex] cm
Therefore, distance between the ship and town A is 19.58 cm.
2). cos(50°) = [tex]\frac{OC}{OB}[/tex]
0.6428 = [tex]\frac{16.96}{OB}[/tex]
OB = 26.38 cm
Therefore, distance between the ship and town B is 26.38 cm.
