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11. PLEASE HELP ME
A ball is thrown into the air with an upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the function h= -16t2 + 48t + 6. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height?

A. 1.5 s; 42 ft

B. 1.5 s; 114 ft

C. 3 s; 6 ft

D. 1.5 s; 54 ft

Respuesta :

DALAU

Answer:

A

Step-by-step explanation:

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lalamcg115

Answer:

A. 1.5 s; 42 ft

Step-by-step explanation:

1.5 sec and will reach a height of 42 feet

that is the vertex

for y=ax^2+bx+c

the x value of teh vertex is  

the y value is found by subsituting the x value of the vertex for x

so

h=-16t^2+48t+6

a=-16

b=48

c=6

x value of vertex is  

subsituting it for x we get

it reaches the max height of 42ft at 1.5 seconds

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