Answer:
[tex]B=-\frac{3}{4}x^6y^4[/tex]
Step-by-step explanation:
One is given the following equation:
[tex]B=(\frac{-3}{16}x^2y)(4x^4y^3)[/tex]
Multiply each term in one of the parenthesis by its like term in the other. Bear in mind, since all of the operations in this equation are multiplication, one doesn't have to multiply every single term by another in the parenthesis, one only has to multiply like terms to simplify.
[tex]B=(\frac{-3}{16}x^2y)(4x^4y^3)[/tex]
[tex]B=(\frac{-3}{16})(4)(x^2)(x^4)(y)(y^3)[/tex]
Simplify further, remember, when multiplying two terms with the same base, one can add their exponents to simplify,
[tex]B=(\frac{-3}{16})(4)(x^2)(x^4)(y)(y^3)[/tex]
[tex]B=(\frac{-3*4}{16})(x^2^+^4)(y^1^+^3)[/tex]
[tex]B=(\frac{-3*4}{16})(x^6)(y^4)[/tex]
Now simplify the fraction, remove like terms found in both the numerator and denominator. Remember, (4) is a factor of both (4) and (16):
[tex]B=(\frac{-3*4}{16})(x^6)(y^4)[/tex]
[tex]B=(-\frac{3}{4})(x^6)(y^4)[/tex]
[tex]B=-\frac{3}{4}x^6y^4[/tex]
