Step-by-step explanation:
➤ Solution :-
a)
Given monomials are 21 xy³ and 24x²y²
21 xy³ = 3×7×x×y×y×y
24x²y² = 3×8×x×x×y×y
HCF of 21xy³ and 24x²y²
=> 3×x×y×y
=> 3xy²
HCF of 21xy³ and 24x²y² = 3xy²
b)
Given monomials are 18 ab and 36abc
18 ab = 18×a×b
36abc = 2×18×a×b×c
HCF of 18 ab and 36abc
=> 18×a×b
=> 18ab
HCF of 18 ab and 36abc = 18ab
c)
Given monomials are 4p³q²r , -12pqr² and 16p²q²r²
4p³q²r = 4×p×p×p×q×q×r
-12pqr² = -3×4×p×q×r×r
16p²q²r² = 4×4×p×p×q×q×r×r
HCF of 4p³q²r , -12pqr² and 16p²q²r²
=> 4×p×q×r
=> 4pqr
HCF of 4p³q²r , -12pqr² and 16p²q²r² = 4pqr
Used Concept :-
→ The HCF of two or more numbers is the highest Common factor
→ The product of least common factors is the HCF of the numbers
