harold was 5 years older than Mary. In 10 years he found that 4 times his age exceeded twice Mary's age by only 50. How old were Harold and Mary in the beginning?

Respuesta :


in the beginning 

Harold X+5
Mary X

In 10 years

Harold X+5+10 X+15
Mary X+10 

4(X+15)-2(X+10)=50
4X+60-2X-20=50
2X+40=50
2X=50-40
2X=10
X= 10÷2
X=5

Harold At The Beginning 5+5=10
Mary At The Beginning 5