Enzo and Beatriz are playing games at their local arcade. Incredibly, Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game. When they stopped playing games, Enzo and Beatriz had won the same number of tickets. What is the minimum number of games that Enzo could have played?

Question

03-01-2017
Mathematics

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Enzo and Beatriz are playing games at their local arcade. Incredibly, Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game. When they stopped playing games, Enzo and Beatriz had won the same number of tickets. What is the minimum number of games that Enzo could have played?

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agaue agaue · Answer 1 · 2018-09-07T17:15:32+02:00

Given :Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game.We need to find the minimum number of games that Enzo could have played to win the same number of tickets.

The minimum number of games that Enzo could have played to win the same number of tickets Will be the least common multiple of 11 and 5.

The factors of 11 and 5 are

11=11x1

5= 5x1

Least common multiply = 11x5=5.

The minimum number of games that Enzo could have played to win the same number of tickets is 55.

ap8997154 ap8997154 · Answer 2 · 2022-04-26T05:35:52+02:00

The Least Common Multiple is the smallest positive integer. The minimum number of games that Enzo will play is 11.

What is LCM?

The least common multiple that is divisible by both a and b is the smallest positive integer, lowest common multiple, or smallest common multiple of two numbers a and b, generally indicated by LCM.

As it is given the number of tickets that Enzo wins in every arcade game is 5 tickets, while the number of tickets that Beatriz wins in every arcade game is 11 tickets.

Now since we need to find the number of games each Enzo and Beatriz played such that the number of tickets with both of them is equal. Therefore, we need to calculate the LCM of both 5 and 11.

As the LCM of 5 and 11 is 55. Thus, the minimum number of games that Enzo needs to play so that the number of tickets with both of them is equal can be written as,

[tex]\text{Number of games}=\dfrac{\text{Number of total tickets}}{\text{Number of tickets per game}}\\\\\text{Number of games}=\dfrac{55}{5} = 11[/tex]

Thus, the minimum number of games that Enzo will play is 11.

Learn more about LCM:

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