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Charles Law

A balloon of helium was put in the freezer at -23°C. Its volume at this temperature was 2.5 liters. It was removed from the freezer. Eventually, it reached a temperature of 177°C. What would its volume be at this temperature? (Neglect any force used to stretch the rubber balloon.) HELP ASAP

A. 1.4
B. 45000
C. 4.5
D. 0.22

Respuesta :

Antdog159
The answer can't be A because it is the amount in liters and D is less than the average B only gives the full value non right of the decimal so the answer is C

Answer : The volume at [tex]177^oC[/tex] will be, (C) 4.5 L

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

[tex]V\propto T[/tex]

or,

[tex]\frac{V_1}{V_2}=\frac{T_1}{T_2}[/tex]

where,

[tex]V_1[/tex] = initial volume of gas = 2.5 L

[tex]V_2[/tex] = final volume of gas = ?

[tex]T_1[/tex] = initial temperature of gas = [tex]-23^oC=273+(-23)=250K[/tex]

[tex]T_2[/tex] = final temperature of gas = [tex]177^oC=273+177=450K[/tex]

Now put all the given values in the above formula, we get the final volume of the gas.

[tex]\frac{2.5L}{V_2}=\frac{250K}{450K}[/tex]

[tex]V_2=4.5L[/tex]

Therefore, the volume at [tex]177^oC[/tex] will be, (C) 4.5 L

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