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A race car has a mass of 710 kg. It starts from rest and travels 40 m in 3.0 s. The car is uniformly accelerated during the entire time. What net force is applied to it

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asuwafohjames

The net force applied to it is 6311.9 N.

To calculate the net force to the car, first, we need to find the acceleration using the equation of motion.

Force: This as be defined as the product of mass and acceleration of a body. The S.I unit of force is Newton (N)

⇒ Formula

  • S = ut+at²/2................. Equation 1

⇒ Where:

  • u = Initial velocity
  • S = Distance
  • t = Time
  • a = acceleration

From the question,

 ⇒Given:

  • S = 40 m
  • t = 3.0 s
  • u = 0 m/s (at rest)

⇒ Substitute these values into equation 1

  • 40 = 0(3)+a(3²)/2

⇒ Solve for a

  • 9a = 80
  • a = 80/9
  • a = 8.89 m/s²

⇒ To get the force, we use the formula below

  • F = ma    .................... Equation 2

⇒ Where:

  • F = Force applied
  • m = mass of the car

⇒ Given:

  • m = 710 kg
  • a = 8.89 m/s²

⇒ Substitute these values into equation 2

  • F = 710(8.89)
  • F = 6311.9 N

Hence the net force applied to it is 6311.9 N.

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