Answer:
[tex]4x^{3}[/tex]
Step-by-step explanation:
Given:
[tex](\frac{192x^{12}}{3x^{3}} )^{\frac{1}{3}}[/tex]
Apply exponent rule of distribution:
[tex]\frac{(192x^{12})^{\frac{1}{3}}}{(3x^{3})^{\frac{1}{3}}}[/tex]
Simplify the numerator:
[tex]\\\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{(3x^{3})^{\frac{1}{3}}}[/tex]
Simplify the denominator:
[tex]\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{3^\frac{1}{3}x}}[/tex]
Simplify:
[tex]4x^{3}[/tex]
-> To explain this party since it is a bigger jump, [tex]3^{\frac{1}{3}}x[/tex] is on the top and the bottom, so it becomes a one. We are left with a four on the top, and using properties of exponents 4 - 1 = 3, explaining why we have [tex]x^{3}[/tex] leftover too.
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
