Explanation:
Since the weight hangs motionless from the spring, the weight is not in motion and is balanced from vertical components of force ( the spring force and the mg of the weight) so
[tex]f _s = mg[/tex]
where f s is the force of the spring.
Now, we can use Hooke Law
[tex]f _{s} = kx[/tex]
where k is the spring constant and x is the displacement of length the spring is stretched.
We know that mg=fs so
[tex] mg = kx[/tex]
mg=w so
[tex]w = kx[/tex]
k is 75 and x is 0.333
so
[tex]x = 75 \: \frac{n}{m} \times 0.33 \: m[/tex]
[tex]x = 24.975 \: n[/tex]
or
25 N or 24.98 N
