Answers:
[tex]\sin(30^{\circ}) = \frac{1}{2}\\\\\\\cos(30^{\circ}) = \frac{\sqrt{3}}{2}\\\\\\\tan(60^{\circ}) = \sqrt{3}\\\\[/tex]
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Work Shown:
Problem 1
[tex]\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(30^{\circ}) = \frac{7}{14}\\\\\sin(30^{\circ}) = \frac{1}{2}\\\\[/tex]
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Problem 2
[tex]\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(30^{\circ}) = \frac{7\sqrt{3}}{14}\\\\\cos(30^{\circ}) = \frac{\sqrt{3}}{2}\\\\[/tex]
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Problem 3
[tex]\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(60^{\circ}) = \frac{7\sqrt{3}}{7}\\\\\tan(60^{\circ}) = \sqrt{3}\\\\[/tex]
