10 A fixed quantity of gas is placed inside a container of fixed volume at a temperature of
27°C. The gas has a pressure, P.
Which expression shows the pressure of the gas at 57°C?
A P2=(27/57) P
B
P2=(57/27) P
P2=(300/330) P
с
D
P2=(330/300) P

Gay-Lussac's law states that the pressure of a given mass of gas varies directly with the absolute temperature of the gas when the volume is kept constant.

Mathematically, it can be written as:

P/T = k

A gas has a pressure P at 27 °C and we want to find the expression to calculate its pressure at 57°C.

Step 1: Convert the temperatures to the Kelvin scale.

We do so by summing 273.15.

K = 27 + 273.15 = 300 K

K = 57 + 273.15 = 330 K

Step 2: Apply Gay-Lussac's law.

P2/330 = P/300

P2 = (300/330) P

A gas has a pressure P at 27 °C. To calculate its pressure at 57°C we use an expression derived from Gay-Lussac's law:

C) P2 = (300/330) P

Learn more about Gay-Lussac's law here: https://brainly.com/question/24691513

10 A fixed quantity of gas is placed inside a container of fixed volume at a temperature of 27°C. The gas has a pressure, P. Which expression shows the pressure of the gas at 57°C? A P2=(27/57) P B P2=(57/27) P P2=(300/330) P с D P2=(330/300) P

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What does Gay-Lussac's law state?

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10 A fixed quantity of gas is placed inside a container of fixed volume at a temperature of
27°C. The gas has a pressure, P.
Which expression shows the pressure of the gas at 57°C?
A P2=(27/57) P
B
P2=(57/27) P
P2=(300/330) P
с
D
P2=(330/300) P