For a solution to be tested in this experiment and must be buffered to pH of 10, the [OH-] change will be, The hydroxide concentration would be higher and the formation of insoluble hydroxide salts with Mg^2 and Ca^2 would cause the determined concentration of water hardness to be too low.
Generally, the equation for the Total hardness is mathematically given as
[tex]T=\frac{A*D*1000}{B}[/tex]
Where
[tex]D=\frac{molarity}{0.01}[/tex]
D=0.02/0.01=2
Therefore
[tex]T=\frac{A*D*1000}{B}\\\\T=\frac{20.4*2*1000}{25}[/tex]
T=1632ppm
in conclusion, The hydroxide concentration would be higher .
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The solution to be tested in this experiment must be buffered to a pH of 10. If the pH is high to 12, the change of [OH-] is 1632 ppm.
OH- ion is the hydroxide ion or hydroxyl ion. It is made up of a hydrogen and oxygen ion with a covalent bond.
[tex]A =\dfrac{A \times D \times 1000}{T} \\[/tex]
The buffered pH is 10
The higher pH is 12
D = molarity divided by 0.01, that is the pH
[tex]D = \dfrac{molarity }{0.01}\\\\D = \dfrac{0.02 }{0.01} = 2[/tex]
Now, putting the values in the first equation
[tex]A =\dfrac{20.4 \times 2 \times 1000}{25} = 1632 \;ppm[/tex]
Thus, the correct option is the change in hydroxide ion is 1632 ppm.
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